Ring

Pub Mar 18, 2026 Up Jun 11, 2026

Definition 1. A ring is a structure $(R, +, \cdot)$ such that:

  1. $(R, +)$ is an abelian group.

  2. $(R, \cdot)$ is a monoid.

  3. (Distributivity) For all $a$, $x$, $y\in R$,

    \[\begin{align*} a(x + y) &= ax + ay, \\ (x + y)a &= xa + ya. \end{align*}\]

Example. $\{0\}$, a trivial / zero ring, is the only kind of ring where $0 = 1$.

Definition 2. A ring $(R, +, \cdot)$ is abelian if $(R, \cdot)$ is abelian.

Definition 3. A unit of a ring is a multiplicatively invertible element.

Definition 4. Let $R$ be a ring, $a \in R$ and $n \in \N$. $a^n$ is defined recursively:

  1. \[a^0 = 1.\]
  2. \[a^{n + 1} = a^n \cdot a.\]

For $n \in \N^+$, we have

\[a^n = \underbrace{a \cdot \cdots \cdot a}_{\text{$n$ times}}.\]

Proposition 1. In a ring $R$, $0$ is an absorbing element with respect to multiplication: For all $a \in R$,

\[a \cdot 0 = 0 \cdot a = 0.\]

Proof.

\[\begin{align*} a \cdot 0 &= a \cdot (1 - 1) = a \cdot 1 - a \cdot 1 = 0, \\ 0 \cdot a &= (1 - 1) \cdot a = 1 \cdot a - 1 \cdot a = 0. \end{align*}\]

Proposition 2. In a non-zero ring $R$, $0$ is not invertible.

Proof. Otherwise, there would be an $x \in R$ such that

\[0 = 0 \cdot x = 1.\]